Integrand size = 12, antiderivative size = 8 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=\operatorname {PolyLog}\left (2,-\frac {a}{x}\right ) \]
[Out]
Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.50, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2497} \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=\operatorname {PolyLog}\left (2,1-\frac {a+x}{x}\right ) \]
[In]
[Out]
Rule 2497
Rubi steps \begin{align*} \text {integral}& = \text {Li}_2\left (1-\frac {a+x}{x}\right ) \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(34\) vs. \(2(8)=16\).
Time = 0.00 (sec) , antiderivative size = 34, normalized size of antiderivative = 4.25 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=-\log \left (-\frac {a}{x}\right ) \log \left (\frac {a+x}{x}\right )-\operatorname {PolyLog}\left (2,-\frac {-a-x}{x}\right ) \]
[In]
[Out]
Time = 0.42 (sec) , antiderivative size = 9, normalized size of antiderivative = 1.12
method | result | size |
derivativedivides | \(\operatorname {dilog}\left (1+\frac {a}{x}\right )\) | \(9\) |
default | \(\operatorname {dilog}\left (1+\frac {a}{x}\right )\) | \(9\) |
risch | \(\operatorname {dilog}\left (1+\frac {a}{x}\right )\) | \(9\) |
parts | \(\ln \left (\frac {a +x}{x}\right ) \ln \left (x \right )+\frac {\ln \left (x \right )^{2}}{2}-\operatorname {dilog}\left (\frac {a +x}{a}\right )-\ln \left (x \right ) \ln \left (\frac {a +x}{a}\right )\) | \(41\) |
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.38 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx={\rm Li}_2\left (-\frac {a + x}{x} + 1\right ) \]
[In]
[Out]
\[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=\int \frac {\log {\left (\frac {a}{x} + 1 \right )}}{x}\, dx \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 59 vs. \(2 (7) = 14\).
Time = 0.19 (sec) , antiderivative size = 59, normalized size of antiderivative = 7.38 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=-{\left (\log \left (a + x\right ) - \log \left (x\right )\right )} \log \left (x\right ) + \log \left (a + x\right ) \log \left (x\right ) - \frac {1}{2} \, \log \left (x\right )^{2} + \log \left (x\right ) \log \left (\frac {a + x}{x}\right ) - \log \left (x\right ) \log \left (\frac {x}{a} + 1\right ) - {\rm Li}_2\left (-\frac {x}{a}\right ) \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 68 vs. \(2 (7) = 14\).
Time = 0.30 (sec) , antiderivative size = 68, normalized size of antiderivative = 8.50 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=-\frac {a^{3} {\left (\frac {1}{\frac {a + x}{x} - 1} - \log \left (\frac {{\left | a + x \right |}}{{\left | x \right |}}\right ) + \log \left ({\left | \frac {a + x}{x} - 1 \right |}\right )\right )} + \frac {a^{3} \log \left (\frac {a + x}{x}\right )}{{\left (\frac {a + x}{x} - 1\right )}^{2}}}{2 \, a^{2}} \]
[In]
[Out]
Time = 1.45 (sec) , antiderivative size = 8, normalized size of antiderivative = 1.00 \[ \int \frac {\log \left (\frac {a+x}{x}\right )}{x} \, dx=\mathrm {polylog}\left (2,-\frac {a}{x}\right ) \]
[In]
[Out]